wrightka said:
A camper leaves the campsite walking due east at 3.5 mph. Another camper leaves the campsite at the same time but travels due west. In two hours the campers will be 15 miles apart. What is the walking rate of the second camper?
I have no clue except that rate = distance/time.
Another clue would be to draw a sketch:
B..................................C..............................A
C is the campsite.
A & B are the positions of the campers after 2 hours.
Let the speed of B be V[sub:lr7phn5z]b[/sub:lr7phn5z] ---> rate of walking of the second camper.
In 2 hours B walks the distance = CB = V[sub:lr7phn5z]b[/sub:lr7phn5z] * 2 miles .......................(1)
In 2 hours A walks the distance = CA = 3.5 * 2 miles......................................(2)
Now what ......