Another radical, but to the cubed root

kingchris626

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Aug 4, 2010
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10?4m^4 - 3m?32m

What I've come up with is:

10?4 x (?m^2)^2 - 6m?4m

I'm kind of lost and probably off track. Not sure where to go. Please assist. Thanks
 
kingchris626 said:
10?(4m^4) - 3m?(32m)

Please put parentheses around radicands.

Examine the radicands for squares. 4 is (2)(2). m^4 is (m^2)(m^2), 32 is (2^2)(2^2)(2), etc. It's the squares that simplify. Every pair of identical factors (squares) under the radical sign simplifies to one factor (square's root) "in front" of the radical sign.

10 ?(4m^4) - 3m ?(32m)

10 ?(2^2 * m^2 * m^2) - 3m ?(2^2 * 2^2 * 2m)

10 * 2 * m^2 - 3m * 2 * 2 * ?(2m)

20 m^2 - 12 m ?(2m)
 
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