The Question asks:
Frank and June play darts. They take turns shooting at a target. The winner is the one who manage to hit the bull's eye center first. Previous contests credited Frank with 2 to 5 odds to hit the center in one shot, while June's odds were 3 to 6. If June shoots first, what is the probability that June beats Frank?
I converted the odds to probability,
P(F) = 2/7 and P(J) = 1/3
To look at them more clearly, P(F) = 6/21 and P(J) = 7/21
So I know that the probability of June winning after just one shot is 7/21 or 1/3. But I'm not sure how to use this to compute the probability than June beats Frank.
Thank you for your help
Frank and June play darts. They take turns shooting at a target. The winner is the one who manage to hit the bull's eye center first. Previous contests credited Frank with 2 to 5 odds to hit the center in one shot, while June's odds were 3 to 6. If June shoots first, what is the probability that June beats Frank?
I converted the odds to probability,
P(F) = 2/7 and P(J) = 1/3
To look at them more clearly, P(F) = 6/21 and P(J) = 7/21
So I know that the probability of June winning after just one shot is 7/21 or 1/3. But I'm not sure how to use this to compute the probability than June beats Frank.
Thank you for your help