Linty Fresh
Junior Member
- Joined
- Sep 6, 2005
- Messages
- 58
A parcel delivery service will deliver a package only if the length plus girth (distance around) does not exceed 108 inches. Find the dimensions of a rectangular box with square ends that satisfies the delivery service's restriction and has maximum volume. What is the maximum volume?
OK, I started with Perimeter P=2x+2y and Volume V=lwh:
108=2x+2y
y=(108-2x)/2=54-x
But I couldn't figure out a way to calculate the squares cut out at the end. So I started again:
x=length of side cut out
length=L-2x
width=W-2x
P=2L+2W=2(L-2x)+2(W-2x)
108=2L-4x+2W-4x
54=L+W-4x
And I get stuck here. I'm sure the answer involves either substituting the perimeter equation into the volume equation or vice-versa, but I can't figure out how to wind up with one variable. Am I on the right track, or do I need to go back to square one?
Thanks so much!
OK, I started with Perimeter P=2x+2y and Volume V=lwh:
108=2x+2y
y=(108-2x)/2=54-x
But I couldn't figure out a way to calculate the squares cut out at the end. So I started again:
x=length of side cut out
length=L-2x
width=W-2x
P=2L+2W=2(L-2x)+2(W-2x)
108=2L-4x+2W-4x
54=L+W-4x
And I get stuck here. I'm sure the answer involves either substituting the perimeter equation into the volume equation or vice-versa, but I can't figure out how to wind up with one variable. Am I on the right track, or do I need to go back to square one?
Thanks so much!