mathstresser
Junior Member
- Joined
- Jan 28, 2006
- Messages
- 134
Evaluate the line integral, where C is the given curve.
\(\displaystyle \L\\\int_{c} zdx+xdy+ydz\)
\(\displaystyle C: x=t^2, y=t^3, z=t^2, 0<=t<=1\)
I do
\(\displaystyle \L\\\int_{0}^{1}(t^2)(2t) + (t^2)(3t^2) + (t^3)(2t) dt\)
I get 3/2.
Is that the only thing I need to do?
Do I need to do anything with
\(\displaystyle \L\\\sqrt((dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2)\)
???
\(\displaystyle \L\\\int_{c} zdx+xdy+ydz\)
\(\displaystyle C: x=t^2, y=t^3, z=t^2, 0<=t<=1\)
I do
\(\displaystyle \L\\\int_{0}^{1}(t^2)(2t) + (t^2)(3t^2) + (t^3)(2t) dt\)
I get 3/2.
Is that the only thing I need to do?
Do I need to do anything with
\(\displaystyle \L\\\sqrt((dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2)\)
???
