Can anyone give me a clue as how to approach this? (The answer is but how do I get there?)
D dangerman77 New member Joined Dec 18, 2005 Messages 6 Dec 19, 2005 #1 Can anyone give me a clue as how to approach this? (The answer is but how do I get there?)
pka Elite Member Joined Jan 29, 2005 Messages 11,976 Dec 19, 2005 #2 The antiderivative of log(x) is given by: \(\displaystyle \L \int {\log (x)dx = x\log (x) - x}\). So for problem just do integration by parts twice.
The antiderivative of log(x) is given by: \(\displaystyle \L \int {\log (x)dx = x\log (x) - x}\). So for problem just do integration by parts twice.
D dangerman77 New member Joined Dec 18, 2005 Messages 6 Dec 19, 2005 #3 Thanks pka! I appreciate the quick (and helpful!) response.