Another Difficult Derivative

Jason76

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Oct 19, 2012
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\(\displaystyle y = 3x^{3} + 2x^{2} + x + 5\)

Basically you have to factor the cube and the square. That's the challenge. But I can do the square.

Book answers (How did it get there?)

\(\displaystyle 9x^{2} + 4x + 1\)

\(\displaystyle x = 3\)

\(\displaystyle y = 94\) = slope of the tangent line at \(\displaystyle x = 3\)
 
I would like to first confirm that the instructions tell you to use the limit-definition for determining the derivative. (Same as in your previous thread.) Is this correct?

PS: The posted cubic polynomial does not factor
 
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