Another Algebra Problem

J

Jason76

Senior Member
Joined
Oct 19, 2012
Messages
1,180
\(\displaystyle 4(2x - 3)(5x^{2} + 2)^{3} + 30x(2x - 3)^{2}(5x^{2} + 2)^{2}\)

becomes

\(\displaystyle 2(2x - 3)(5x^{2} + 2)^{2}[2(5x^{2} + 2) + 15x(2x - 3)]\)

Please give me some hints on how the top became the bottom. I have no clue on this one.
 
Last edited:
Jason76 said:
\(\displaystyle 4(2x - 3)(5x^{2} + 2)^{3} + 30x(2x - 3)^{2}(5x^{2} + 2)^{2}\)

becomes

\(\displaystyle 2(2x - 3)(5x^{2} + 2)^{2}[2(5x^{2} + 2) + 15x(2x - 3)]\)

Please give me some hints on how the top became the bottom. I have no clue on this one.
Click to expand...

Jason, as it was suggested to you before - you ought to enrol in a rigorous/multi-year algebra course.

Here simply the common factors are being factored out.

If you have

4 * A * B3 + 30*x*A*B2

that can be factorized into

2*A*B2 * [2*B + 15*x*A] ← Incorrect - it should be → 2*A*B2 * [2*B + 15*x]
 
Last edited by a moderator:
Subhotosh Khan said:
Thats Sir Michael to us......
Click to expand...
If I only was a Sir. I love it. I have been called that by many on this forum. Hate to tell the truth, but the "sr" at the beginning is simply my first initial and second initial. But I'll let you all call me Sir. :mrgreen:
 
\(\displaystyle 4(2x - 3)(5x^{2} + 2)^{3} + 30x(2x - 3)^{2}(5x^{2} + 2)^{2}\)

becomes

\(\displaystyle 2(2x - 3)(5x^{2} + 2)^{2}[2(5x^{2} + 2) + 15x(2x - 3)]\)


so the greatest common factor of:

\(\displaystyle 2(2x - 3)(5x^{2} + 2)^{2}\)

is divided by each polynomial term in the original equation.
 
Last edited:
Jason76 said:
\(\displaystyle 4(2x - 3)(5x^{2} + 2)^{3} + 30x(2x - 3)^{2}(5x^{2} + 2)^{2}\)

becomes

\(\displaystyle 2(2x - 3)(5x^{2} + 2)^{2}[2(5x^{2} + 2) + 15x(2x - 3)]\)


so the greatest common factor of:

\(\displaystyle 2(2x - 3)(5x^{2} + 2)^{2}\)

is divided by each polynomial term in the original equation.
Click to expand...
Jason

What are you talking about? In your original post for this thread, you asked why one expression is equal to another expression. It was explained to you that the one expression was factored to get the other. Neither expression involved division. Are you referring now to some other thread?
 
Jason76 said:
\(\displaystyle 4(2x - 3)(5x^{2} + 2)^{3} + 30x(2x - 3)^{2}(5x^{2} + 2)^{2}\)

becomes

\(\displaystyle 2(2x - 3)(5x^{2} + 2)^{2}[2(5x^{2} + 2) + 15x(2x - 3)]\)


so the greatest common factor of:

\(\displaystyle 2(2x - 3)(5x^{2} + 2)^{2}\)

is divided by each polynomial term in the original equation.
Click to expand...

You should say instead - the greatest common factor (GCF) has been factored out.
 
You must log in or register to reply here.
Top