If ab=5 and a+b=4, then a3+b3=?
So far I have:
(a+b)3=a3+3a2b+3ab2+b3=43
a3+b3+3a2b+3ab2=64
a3+b3+3ab(a+b)=64
a3+b3+3(5)(4)=64
a3+b3=4
But the only way a+b and a3+b3 could be the same would be if a and b were 1, which would mean a+b=2.
So is my answer right?
So far I have:
(a+b)3=a3+3a2b+3ab2+b3=43
a3+b3+3a2b+3ab2=64
a3+b3+3ab(a+b)=64
a3+b3+3(5)(4)=64
a3+b3=4
But the only way a+b and a3+b3 could be the same would be if a and b were 1, which would mean a+b=2.
So is my answer right?