Anne running to helicopter word problem.

[mdd]

I would appreciate someone verifying my equation.

Anne is standing on a straight road and wants to reach her helicopter, which is located 2 miles down the road from her, a mile from the road in the field. She plans to run down the road, then cut diagonally across the field to reach the helicopter. She can run 5 mph on the road and 3 mph in the field.

a) Where should she leave the road to reach her helicopter in 42 min.?

My equation is the sqr. root of (2-X) sqrd + 1, all of which is over 3 + X/5 = .7

If this equation is correct, will someone outline how to enter this on my graphing calculator? I can not seem to get an intercept.

Thank you,
mdd[/img][/tex]

 

[Mrspi]

I would appreciate someone verifying my equation.

Anne is standing on a straight road and wants to reach her helicopter, which is located 2 miles down the road from her, a mile from the road in the field. She plans to run down the road, then cut diagonally across the field to reach the helicopter. She can run 5 mph on the road and 3 mph in the field.

a) Where should she leave the road to reach her helicopter in 42 min.?

My equation is the sqr. root of (2-X) sqrd + 1, all of which is over 3 + X/5 = .7

If this equation is correct, will someone outline how to enter this on my graphing calculator? I can not seem to get an intercept.

Thank you,
mdd[/img][/tex]

I interpret your equation this way:

√[(2 - x)<SUP>2</SUP> + 1] / 3 + (x / 5) = .7

Subtract .7 from both sides, and then enter the resulting equation in your calculator...

y = √[(2 - x)<SUP>2</SUP> + 1] / 3 + (x / 5) - .7

It worked for me....

 

[mdd]

Thank you for your response. Did you get an x value of 1.8?

mdd