Angles Questions

[Angel Haroon]

So Far I don't know how to solve this.?

 

[Deleted member 4993]

So Far I don't know how to solve this.?

Do you know:

<AQX + <XOP + <POB = ?

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520​

Please share your work/thoughts about this problem.

 

[Angel Haroon]

<AOX + <XOP + <POB =180
i.e. 42 + 4x + <POB= 180

and
<AOQ + <QOY + <BOY =180
i.e. <AOQ + 6x + 24 =180

IN BOTH CASES WE HAVE TWO UNKNOWN VALUES.

 

[joshuaa]

if you have two unknowns and two equations, you can find them both

you have two options to use, substitution or elimination

 

[Dr.Peterson]

<AOX + <XOP + <POB =180
i.e. 42 + 4x + <POB= 180

and
<AOQ + <QOY + <BOY =180
i.e. <AOQ + 6x + 24 =180

IN BOTH CASES WE HAVE TWO UNKNOWN VALUES.

Do you see that AOQ and POB are vertical angles? Call them y, and solve for x.

 

[Steven G]

if you have two unknowns and two equations, you can find them both

you have two options to use, substitution or elimination

That is not true at all. Suppose one equation is 3x+4y =7. It clearly has two unknowns.
Now suppose the 2nd equation is 4u-11w = 13. This too has two unknowns.

In fact, the above system has two equations in 4 unknowns!

Assuming that the OP's equations are correct the system has two equations in three unknowns.

It does turn out that you can express one unknown in one eq in terms of one unknown in the other equation. My concern is that you never mentioned this.