These are ALWAYS measured from the horizontal. ALWAYS!!!!
If you've an angle of elevation from the top of the tree, the point in question must be ABOVE the top of the tree.
My first guess would be that the problem statement means the angle of elevation TO the top of the tree FROM the spot on the gound 30 ft from the base. That would be an entirely different problem.
Hey Mathisconfusing, did you ever get that calc fixed? You would not do what you said to find the measure of the opposite side. You should have your problem set up like this:
\(\displaystyle \L\bold Tan25=\frac{x}{30}\)
Now remember you gotta do the inverse Tan \(\displaystyle (Tan^{-1})\). I gave you this website for a reason http://wright.nasa.gov/airplane/trig.html because it has all the inverse Tan operations on there. Go to the bottom where it says Tan(x), find what \(\displaystyle Tan25\) equals and solve for \(\displaystyle x\) (the opposite side).
if x is the height of the tree, then tan(25) = x/30
multiply both sides by 30 ...
x = 30tan(25)
I already told you how to set up your calculator in degree mode ... just type in the right side of the last equation on your home screen and press [enter] ... you'll get the value for x.[/tex]
Please don't forget that the problem statement is totally wrong if that drawing is correct. You should not be expected to provide correct translations of incorrect problem statements.
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