renegade05
Full Member
- Joined
- Sep 10, 2010
- Messages
- 260
Alright, here is the question:
Analytically find the exact maxiumum and minimum value for
\(\displaystyle f(x)=\sqrt{3}x-cos(2x)\) on the interval \(\displaystyle [-\pi,\pi]\)
I found through differentiating and solving for x when \(\displaystyle f'(x)=0\) that:
QUAD IV: \(\displaystyle x=\frac{5\pi}{6} + \pi K\)
QUAD III: \(\displaystyle x=\frac{2\pi}{3} + \pi K\)
Where K is integer.
My question is, how can I find what values to put in for K so that the equations remain on the interval \(\displaystyle [-\pi,\pi]\) ?
I mean, I plugged everything into my calculator and it looks i get the critical numbers when k = -1 and 0. But how would i find these values for K analytically.
I am sure i am forgetting something fundamental or easy. Please help. Thanks.
Analytically find the exact maxiumum and minimum value for
\(\displaystyle f(x)=\sqrt{3}x-cos(2x)\) on the interval \(\displaystyle [-\pi,\pi]\)
I found through differentiating and solving for x when \(\displaystyle f'(x)=0\) that:
QUAD IV: \(\displaystyle x=\frac{5\pi}{6} + \pi K\)
QUAD III: \(\displaystyle x=\frac{2\pi}{3} + \pi K\)
Where K is integer.
My question is, how can I find what values to put in for K so that the equations remain on the interval \(\displaystyle [-\pi,\pi]\) ?
I mean, I plugged everything into my calculator and it looks i get the critical numbers when k = -1 and 0. But how would i find these values for K analytically.
I am sure i am forgetting something fundamental or easy. Please help. Thanks.