As I am just learning this subject I am unsure if I have this correct. Can someone please take a look and let me know if I am correct ? Thanks kindly.
Using this formula:
I = 6/5(1-e^-20t)
I need to briefly explain what happens to I for t> or equal to 0.
My attempt is:
at t=o, I=0. A t progresses, 'I' quickly increases to a limit of 1.2 at approx. 0.62t. From then on, any higher value of t is limited to I=1.2.
Using this formula:
I = 6/5(1-e^-20t)
I need to briefly explain what happens to I for t> or equal to 0.
My attempt is:
at t=o, I=0. A t progresses, 'I' quickly increases to a limit of 1.2 at approx. 0.62t. From then on, any higher value of t is limited to I=1.2.