An old guy who forgets his High school algebrae

[Jackietaylor]

Hi,

I have what I think may be a somewhat simple algabrae problem for some of you but I cannot for the life of me remember how to do it from High School. I am trying to determine what x,y and z are in this problem.

107000 X (x) + 4300 X (y) + 4050 X(z) = 394,039.80 Each of the numbers should be no more than two decimal places.

Can anyone help me?

Many thanks

 

[Jackietaylor]

Thanks JeffM. That was what I was afraid of. Those three numbers are quantities of three different products whose total cost is the 394,039.80. I"m trying to determine the cost of each unit and the combination of the three would be exactly that amount. I suspect there would not be many differnt combinations if the numbers are limited to two decimal places. The only other information I have is what I suspect the cost "range" to be for each item. Item x is between .19 and .25, item y is between 1.20 and 1.70 and item z is likely between .85 and 1.25. I thought I might be able to create some type of matrix in Excel that might give me the answer but that is likely far beyond my scope of knowledge. I had hoped that perhaps it was just a math problem I coudnt quite grasp.

Thanks,

 

[Yogi]

What is X? Is it supposed to be multiplication or is it actually another variable? If it is multiplication then even with the largest possible prices given by your constraints we get 107000(.25)+4300(1.7)+4050(1.25)=34,822.50, nowhere close to 394,039.80