An isosceles right triangle is inscribed in a circle. If the area of the circle is 16 pi, what is the area of the triangle?
A= pi r2
16 pi =pi r2
16 = r2
4 = r
8 = diameter
Area of Triangle
A = ½ bh
Diameter of circle --> hypotenuse of triangle
Triangle 4 by 4 sqrt 3 by 8
A = ½ (4 * 4 sqrt 3)
A= 4 sqrt 3
????
Is this correct
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A= pi r2
16 pi =pi r2
16 = r2
4 = r
8 = diameter
Area of Triangle
A = ½ bh
Diameter of circle --> hypotenuse of triangle
Triangle 4 by 4 sqrt 3 by 8
A = ½ (4 * 4 sqrt 3)
A= 4 sqrt 3
????
Is this correct
[/list][/tex]