Well guys I haven't been at school when teacher was explaining quations like this:
(cos5x - 5)(5sin5x - 2.5)=0
I may use the rule: one multiplicative must be zero
E.G. cos5x - 5=0 and 5sin5x - 2.5=0
I think I should get 2 solutions but in the answers there is only one. If you don't know what I'm talking about, please solve this on your method
another equation: ctgx(2 - cosx)=0
I get the idea that cosx=0 -----> x= pi/2 + npi
but what to do with 2 - cosx ? again only one answer above x=
(cos5x - 5)(5sin5x - 2.5)=0
I may use the rule: one multiplicative must be zero
E.G. cos5x - 5=0 and 5sin5x - 2.5=0
I think I should get 2 solutions but in the answers there is only one. If you don't know what I'm talking about, please solve this on your method
another equation: ctgx(2 - cosx)=0
I get the idea that cosx=0 -----> x= pi/2 + npi
but what to do with 2 - cosx ? again only one answer above x=