an astronomical telescope

logistic_guy

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An astronomical telescope has its two lenses spaced \(\displaystyle 76.0 \ \text{cm}\) apart. If the objective lens has a focal length of \(\displaystyle 74.5 \ \text{cm}\), what is the magnification of this telescope? Assume a relaxed eye.
 
An astronomical telescope has its two lenses spaced \(\displaystyle 76.0 \ \text{cm}\) apart. If the objective lens has a focal length of \(\displaystyle 74.5 \ \text{cm}\), what is the magnification of this telescope? Assume a relaxed eye.
show us your effort/s to solve this problem.
 
The magnification is determined from this formula:

\(\displaystyle M = - \frac{f_o}{f_e}\)

But we don't have the focal length of the eyepiece, \(\displaystyle f_e\), so we have to find it from the formula of the total focal length.

\(\displaystyle L = f_o + f_e\)
\(\displaystyle 76 = 74.5 + f_e\)

Then

\(\displaystyle M = - \frac{f_o}{f_e} = -\frac{74.5}{76 - 74.5} \approx -50\text{x}\)

where the negative sign means that the image is inverted and \(\displaystyle \text{x}\) means times, in other words, the inverted image is \(\displaystyle 50\) times larger than the real image.
 
First makes post with no work shown and then posts the solution. This is in violation of the posting guidelines.
Reported this OP to the admin---again
 
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