Am I correct?

[Soso]

I have an assignment and I did it but I want to make sure whether my answer is correct
Can any one check my answer please?
State the transformation and then use those transformation to graph the function g(x)=-√-x -2

the points that I plot on the graph are (0.0),(1,1),(4,2)

the final result I got is
(0,-2), (-1,-3), (-4,-4)

 

[Ishuda]

I have an assignment and I did it but I want to make sure whether my answer is correct
Can any one check my answer please?
State the transformation and then use those transformation to graph the function g(x)=-√-x -2

the points that I plot on the graph are (0.0),(1,1),(4,2)

the final result I got is
(0,-2), (-1,-3), (-4,-4)

I assume the function is
g(x) = \(\displaystyle -\sqrt{-x} - 2\)
rather than \(\displaystyle -\sqrt{-x - 2}\) [whats under that square root symbol can be misinterpreted sometime]. That being the case, yes your answers of (0,-2), (-1,-3), (-4,-4) are correct for (x, g(x)). Very Good. However, I'm not sure what you mean by the points on the graph being (0.0),(1,1),(4,2) but what that looks like is the ordered pairs \(\displaystyle (x, \sqrt{x})\). Also, the problem says state the transformation and I don't see a statement.

 

[Steven G]

I have an assignment and I did it but I want to make sure whether my answer is correct
Can any one check my answer please?
State the transformation and then use those transformation to graph the function g(x)=-√-x -2

the points that I plot on the graph are (0.0),(1,1),(4,2)

the final result I got is
(0,-2), (-1,-3), (-4,-4)

Let y = sqrt(x) be the base function. The sqrt(-x) is the reflection across the y axis. Then -sqrt(-x) is a reflection across the x- axis. Then -sqrt(-x) - 2 is a transformation down 2 units.

In the end (x,y) becomes (-x, -y-2)