Algebraic Word Problems and 1 Equation

[eaw7777]

1 - A service station attendant is paid time-and-a-half for working over 40 hours per week. Last week the attendant worked 47 hours and earned $631.25. Find the attendant's regular hourly wage.

2 - The charges for a long-distance telephone call are $1.42 for the first 3 minutes and $.65 for each additional minute or fraction of a minute. If charges for a call were $10.52, how many minutes did the phone call last?

3 - S=2(pie)r[sup:1vorch32]2[/sup:1vorch32] + 2 (pie)rh *Solve for h*

Thank you!

 

[Deleted member 4993]

1 - A service station attendant is paid time-and-a-half for working over 40 hours per week. Last week the attendant worked 47 hours and earned $631.25. Find the attendant's regular hourly wage.

2 - The charges for a long-distance telephone call are $1.42 for the first 3 minutes and $.65 for each additional minute or fraction of a minute. If charges for a call were $10.52, how many minutes did the phone call last?

3 - S=2(pie)r[sup:3579b5ok]2[/sup:3579b5ok] + 2 (pie)rh *Solve for h*

Thank you!

1. Define unknowns
how many minutes did the phone call last.
Let wage = W

2. Define unknowns
how many minutes did the phone call last.
Let # of minutes = M

3. S=2(pi)r[sup:3579b5ok]2[/sup:3579b5ok] + 2 (pi)rh *Solve for h*
Isolate 'h'

S-2(pi)r[sup:3579b5ok]2[/sup:3579b5ok] = 2 (pi)rh

Now continue.....

Please share your work with us, indicating exactly where you are stuck - so that we may know where to begin to help you

 

[eaw7777]

Thank you!
Working on them now and will post back.

 

[BigGlenntheHeavy]

\(\displaystyle I'll \ do \ one \ for \ you \ to \ get \ you \ started.\)

\(\displaystyle 1) \ let \ x \ = \ regular \ hourly \ rate, \ then \ \frac{3x}{2} \ = \ overtime \ hourly \ rate.\)

\(\displaystyle Ergo, \ 40x \ + \ 7\bigg(\frac{3x}{2}\bigg) \ = \ 631.25, \ \implies \ x \ = \ \$12.50\)

\(\displaystyle Check: \ 40(12.50)+7(18.75) \ = \ 631.25\)

 

[eaw7777]

Thanks!
In the equation, what does the 3x2 stand for?
Having trouble with this last word problem, here is what I have come up with.
$1.423M+$.65(60M)=$10.52

 

[Deleted member 4993]

2 - The charges for a long-distance telephone call are $1.42 for the first 3 minutes and $.65 for each additional minute or fraction of a minute. If charges for a call were $10.52, how many minutes did the phone call last?


2. Define unknowns
how many minutes did the phone call last.
Let # of minutes = M

Assume M > 3 (you'll need to confirm that at the end)

Then

1.42 + (M-3) * 0.65 = 10.52

(M - 3) * 0.65 = 9.10

M - 3 = 9.10/0.65

now continue...

 

[eaw7777]

Thanks so much!
Here's what I got:
1.42 + (M-3) x .65 = 10.52
-1.42 + M-3 x .65/.65 = 10.52-1.42/.65
M-3 = 9.10/.65
M-3+3 = 14+3
M =17

 

[Deleted member 4993]

Thanks so much!
Here's what I got:
1.42 + (M-3) x .65 = 10.52
-1.42 + M-3 x .65/.65 = 10.52-1.42/.65
M-3 = 9.10/.65
M-3+3 = 14+3
M =17 <<<< That's what I got too