mathwannabe
Junior Member
- Joined
- Feb 20, 2012
- Messages
- 122
Hello everybody 
Here it is:
1) \(\displaystyle \dfrac{(a-1)^2}{(a-b)(a-c)}+\dfrac{(b-1)^2}{(b-a)(b-c)}+\dfrac{(c-1)^2}{(c-a)(c-b)}\)
\(\displaystyle a\neq c\), \(\displaystyle c\neq b\), \(\displaystyle a\neq b\)
I got to:
\(\displaystyle \dfrac{-a^2b+a^2c-b^2c+ab^2-ac^2+bc^2}{(a-b)(b-c)(c-a)}=\)
\(\displaystyle =\dfrac{-ab(a-b)-ac(c-a)-bc(b-c)}{(a-b)(b-c)(c-a)}\)
I have done 50 of these today, I just can't think anymore... I can feel my forehead skin stretching due to severe brain swelling x)
Here it is:
1) \(\displaystyle \dfrac{(a-1)^2}{(a-b)(a-c)}+\dfrac{(b-1)^2}{(b-a)(b-c)}+\dfrac{(c-1)^2}{(c-a)(c-b)}\)
\(\displaystyle a\neq c\), \(\displaystyle c\neq b\), \(\displaystyle a\neq b\)
I got to:
\(\displaystyle \dfrac{-a^2b+a^2c-b^2c+ab^2-ac^2+bc^2}{(a-b)(b-c)(c-a)}=\)
\(\displaystyle =\dfrac{-ab(a-b)-ac(c-a)-bc(b-c)}{(a-b)(b-c)(c-a)}\)
I have done 50 of these today, I just can't think anymore... I can feel my forehead skin stretching due to severe brain swelling x)