joannamartinez
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The width of a rectangle is fixed at 19cm. What lengths will make the perimeter greater than 82 cm? I do not know how to do this. Please advise. Thank you.
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Algebra
- Thread starter joannamartinez
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BigGlenntheHeavy
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\(\displaystyle P_{Rect} \ = \ 2(l)+2(19) \ = \ 2l+38\)
\(\displaystyle Hence, \ 2l \ +38 \ > \ 82, \ so \ l \ > \ ?\)
\(\displaystyle Hence, \ 2l \ +38 \ > \ 82, \ so \ l \ > \ ?\)
joannamartinez
Junior Member
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The answer is 22. Am I correct? Please advise.Thank you.
BigGlenntheHeavy
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Yes, that is correct.
joannamartinez
Junior Member
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Thank you. I appreciate your help.