algebra

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pboland

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If you produce 'x' photo calendars, the average cost per calendar is given by A(x)= -0.4x^2 + 24x +42/x. What is your average cost, if you produce wenty five calendars? Please help.
 
pboland said:
If you produce 'x' photo calendars, the average cost per calendar is given by A(x)= -0.4x^2 + 24x +42/x. What is your average cost, if you produce wenty five calendars? Please help.
Click to expand...
Plug in "25" for "x". Simiplify.

Eliz.
 
I did the long division and my answer is
x = -0.016x^2 + (25/25)x with remainder 42. Is this correct and the answer would be average cost of 0.42
 
The answer I got for:
A(25)=-0.4*(25^2)+24*25+42/25 is 0.35981 so the answer would be 0.35 average cost per calendar. Is this correct?
 
Hmmmm. Your equation is not typed correctly. It should probably be
A(x)= (-0.4x^2 + 24x +42)/x
I don't get your answer either way.
a(25)=(-.4*25^2+24*25+42)/25 =
(-250+600+42)/25 =
392/25 =
15.68
Better save up and buy a calculator. If you show your work we could help by telling you where you went wrong.
 
Thanks for your help. I found where my mistake was. I divided 25 into 42 instead of dividing into the whole equation.
 
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