algebra using negative exponents

[Shannon]

Hi i am having problems with this question, could you please help me!!!

(x to the exponent 3 multiplied by y to the exponent 2) negative 3 exponent on the outside of the brackets
divided by
(x to the exponent 2 multiplied by y to the exponent 3) negative 2 exponent on the outside of the brackets.

hopefully that makes sense let me know thank you

 

[Peachyyy]

hi Shannon,

Does your problem look like this:

[(x³y²)^-3]/[(x²u³)^-2]

If you have an exponent on the outside of parens, then multiply the exponent on the outside of the parens x the exponent on the inside of the parens to get the answer. Like this:

(x³y²)^-3 = x^-9y^-6.

Now, you can't leave an answer with negative exponents, so to get rid of negative exponents, you swap from the top of the division line to the bottom or vice versa. for instance, x^-3/1 would become 1/x³ or 1/x^-3 would become x³ /1.

I hope this makes sense....

 

[Shannon]

thank you that really helped!!! shannon