algebra: solve 2x^2 - 128 = 0
- Thread starter pboland
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- Apr 12, 2005
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I think it's a bad habit. Try this.pboland said:
2x^2 - 128 = 0
2(x^2 - 64) = 0
(x^2 - 64) = 0
(x+8)(x-8) = 0
x = -8, x = 8
In the original demonstration one must REMEMBER that there are two solutions. In the second demonstration, they cannot be avoided.