Algebra Question

Jason76

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Oct 19, 2012
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How does \(\displaystyle 3(x + \Delta x)^{2}\) become \(\displaystyle 3x^{2} + 6x\Delta x + 3(\Delta x)^{2}\) ? Hints? :confused:
 
Last edited:
\(\displaystyle 3(x + \Delta x)^{2}\)

\(\displaystyle 3(x^{2} + 2(x^{2})(\Delta x) + (\Delta x)^{2}\) - Showing the missing step. ;-)

\(\displaystyle 3x^{2} + 6x\Delta x + 3(\Delta x)^{2}\)
 
Last edited:
\(\displaystyle 3(x+Δx)^2=3(x^2+2xΔx+(Δx)^2)=3x^2+6xΔx+3(Δx)^2 \)
 
CORRECTED

\(\displaystyle 3(x + \Delta x)^{2}\)

\(\displaystyle 3(x^{2} + 2(x)(\Delta x) + (\Delta x)^{2}\) - Showing the missing step. :wink:

\(\displaystyle 3x^{2} + 6x\Delta x + 3(\Delta x)^{2}\)
 
CORRECTED

\(\displaystyle 3(x + \Delta x)^{2}\)

\(\displaystyle 3(x^{2} + 2(x)(\Delta x) + (\Delta x)^{2}\)) - Showing the missing step. :wink: \(\displaystyle \ \ \ \ \ \) <------ Jason76, you were missing a close parenthesis in this line and also in the corresponding line of post # 3.

\(\displaystyle 3x^{2} + 6x\Delta x + 3(\Delta x)^{2}\)
.
 
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