Algebra Problem with 0

[Jason76]

\(\displaystyle 12x^{2} - 64 = 0\)

\(\displaystyle x^{2} = \dfrac{64}{12}\)

\(\displaystyle x = \pm \dfrac{64}{12}\)

\(\displaystyle x = \pm \dfrac{16}{3}\)

 

[stapel]

\(\displaystyle 12x^{2} - 64 = 0\)

\(\displaystyle x^{2} = \dfrac{64}{12}\)

\(\displaystyle x = \pm \dfrac{64}{12}\)

How did you get that the square root of 64/12 was 64/12? Are you familiar with "square roots" at all?

 

[Jason76]

\(\displaystyle 12x^{2} - 64 = 0\)

\(\displaystyle x^{2} = \dfrac{64}{12}\)

\(\displaystyle x^{2} = \dfrac{16}{3}\)

\(\displaystyle x = \pm \sqrt{\dfrac{16}{3}}\)

 

[stapel]

\(\displaystyle 12x^{2} - 64 = 0\)

\(\displaystyle x^{2} = \dfrac{64}{12}\)

\(\displaystyle x^{2} = \dfrac{16}{3}\)

\(\displaystyle x = \pm \sqrt{\dfrac{16}{3}}\)

Now rationalize the denominator.