Algebra practice

That would depend on what you mean. What you have written is this:

\(\displaystyle 3\cdot x + \frac{2}{9} + \frac{2\cdot x}{3} = \frac{2}{9}\)

I'm going to guess this is NOT what you intended. Please use arentheses to clarify and remember your Order of Operations!
 
So, 3x + (2/9) + [(2/3)x] = 2/9 is your equation? Which by the way is LOGICALLY EQUIVALENT to as 3x + (2/9) + (2x/ 3) = 2/9.

Well if so, you gather like terms, right? So what is the result of THAT process?
 
KKLover, you gave us this: 3x + [2/9] + (2/3)x = [2/9]

It is evident (by inspection) that the only possible solution is x=0 ?
Can you tell us why?
 
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