Algebra linear function problem

[joannamartinez]

I need help with this problem please. In 1990, the life expectancy of males in a certain country was 61.1 years. In 1996, it was 63.5 years. Let E represent the life expectancy in year t and let t represent the number of years since 1990. The linear function E(t) that fits the data is E(t)= ?t + ?(round to the nearest tenth). Then use the fuunction to predict the life expectancy of males in 2009. E(19)=? (round to the nearest tenth). Please help me with this. Thank you very much.

 

[Deleted member 4993]

I need help with this problem please. In 1990, the life expectancy of males in a certain country was 61.1 years. In 1996, it was 63.5 years. Let E represent the life expectancy in year t and let t represent the number of years since 1990. The linear function E(t) that fits the data is E(t)= ?t + ?(round to the nearest tenth). Then use the fuunction to predict the life expectancy of males in 2009. E(19)=? (round to the nearest tenth). Please help me with this. Thank you very much.

Please share with us your work, indicating exactly where you are stuck - so that we know where to begin to help you.

Equation of a straight line through (x[sub:esmb48iv]1[/sub:esmb48iv], y[sub:esmb48iv]1[/sub:esmb48iv]) and (x[sub:esmb48iv]2[/sub:esmb48iv], y[sub:esmb48iv]2[/sub:esmb48iv]) is:

\(\displaystyle \frac{y \ - \ y_1}{y_2 \ - \ y_1} \ \ = \ \ \frac{x \ - \ x_1}{x_2 \ - \ x_1}\)

In your case y ? E and x ? t

 

[joannamartinez]

Sorry it took so long to reply. I had to refigure the problem. This is what I came up with. The first data points are (0,61.1) and the second is (6,63.5). m=61.1-63.5/0-6= -2.4/-6= 0.4. 61.1*0.4=24.44 and 0.4(19)+61.1=68.7. The linear function of E(t) that fits the data is E(t)= 4t + 61.1. Is this correct? The function of predicted life expectancy of males in 2009 is E(19)=68.7. Is this correct? Please advise. Thank you.

 

[Deleted member 4993]

Sorry it took so long to reply. I had to refigure the problem. This is what I came up with. The first data points are (0,61.1) and the second is (6,63.5). m=61.1-63.5/0-6= -2.4/-6= 0.4. 61.1*0.4=24.44 and 0.4(19)+61.1=68.7.

The linear function of E(t) that fits the data is E(t)= 0.4t + 61.1. <<<< Looks good to me - other than small typo Is this correct?

The function of predicted life expectancy of males in 2009 is E(19)=68.7 <<<< Looks good to me . Is this correct? Please advise. Thank you.