Algebra I help: Solving Quadratics with the Zero Product

Carbunkel

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Jan 23, 2007
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Using Zero Product, how would you solve a problem such as "4x^2+5x+1=0" or something like "5(x+7)^2." I've been looking through my notes to solve said equations; however, to no avail.

Comments will be greatly appreciated, thanks.
 
Factor:

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This should be in any algebra book.

\(\displaystyle \L\\4x^{2}+5x+1=0\)

What 2 numbers when added equal 5 and when multiplied equal 4.

That's right, 4 and 1.

\(\displaystyle \L\\4x^{2}+4x+x+1\)

\(\displaystyle \L\\4x(x+1)+(x+1)\)

Factor:

\(\displaystyle \L\\(4x+1)(x+1)=0\)

Now, what makes this equal 0?. Try \(\displaystyle \frac{-1}{4}, \;\ -1\)
 
Carbunkel said:
Using Zero Product, how would you solve a problem such as "4x^2+5x+1=0" or something like "5(x+7)^2."
5(x + 7)^2 is NOT an equation :shock:
 
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