algebra help??

can someone show me how to solve problems like this?

3(2x+6)-3

1. What do you mean by "solve"? There isn't anything to solve.

2. Your term can be re-written in two different ways:

a) Expand the bracket an collect like terms.

b) Factor out 3 and collect like terms in the bracket.
 
can someone show me how to solve problems like this?

3(2x+6)-3

Here is how you can "solve" it:

\(\displaystyle 3(2x+6)-3=\)

\(\displaystyle =6x+18-3=\)

\(\displaystyle =6x+15\)

(Note >> \(\displaystyle 3(2x+6)\) << use the distributive law to get rid of the brackets (distributive law: >> \(\displaystyle a(b+c)=ab+ac\) << ) >> \(\displaystyle 3(2x+6)=3(2x)+3(6)=6x+18\) <<
(Now we have >> \(\displaystyle 6x+18-3\) <<. Combine like terms. Terms 18 and -3 are like terms. >>\(\displaystyle 18 + (-3)=18-3=15\)
 
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