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algebra help
- Thread starter tina4545
- Start date
tina4545 said:Can anyone help me solve these two problems, need ASAP.
Thank You
1. clear fractions and solve
1-2/3y=9/5-1/5+3/5
2. 18/1/2/3/4
Hi tina4545,
Since you didn't use any grouping symbols, this is what you have:
[1] \(\displaystyle 1-\frac{2}{3}y=\frac{9}{5}-\frac{1}{5}+\frac{3}{5}\)
\(\displaystyle 1-\frac{2}{3}y=\frac{11}{5}\)
\(\displaystyle -\frac{2}{3}y=\frac{11}{5}-1\)
\(\displaystyle -\frac{2}{3}y=\frac{6}{5}\)
\(\displaystyle 10y=-18\)
\(\displaystyle y=-\frac{9}{5}\)
[1] \(\displaystyle 18 \div 1 \div 2 \div 3 \div 4 = \frac{3}{4}\)
Right side should be 13/5masters said:[1] \(\displaystyle 1-\frac{2}{3}y=\frac{9}{5}-\frac{1}{5}+\frac{3}{5}\)
\(\displaystyle 1-\frac{2}{3}y=\frac{11}{5}\)
Denis said:Right side should be 13/5masters said:[1] \(\displaystyle 1-\frac{2}{3}y=\frac{9}{5}-\frac{1}{5}+\frac{3}{5}\)
\(\displaystyle 1-\frac{2}{3}y=\frac{11}{5}\)
So that means 9 - 1 + 3 = 13 ??
D
Deleted member 4993
Guest
Denis said:I need an eye (and head!) exam :x
We knew that - that's what happens when you chase hockey-pucks on shiny ice!!!!
now go sit in the corner!!!!
D
Deleted member 4993
Guest
tina4545 said:Can anyone help me solve these two problems, need ASAP.
Thank You
1. clear fractions and solve
1-2/3y=9/5-1/5+3/5
2. 18/1/2/3/4
You need to use grouping - paranthesis - for the second problem. Is it:
\(\displaystyle \frac{18}{\left [\frac{\frac{1}{2}}{\frac{3}{4}}\right ]}\)
or
\(\displaystyle \frac{\left [\frac{18}{\frac{1}{2}}\right ]}{\frac{3}{4}}}\)
or something else???
I'm already there...thanks for keeping the chair warm!Subhotosh Khan said:now go sit in the corner!!!!
E
Edith
Guest
You have already got your answer from Master. But, getting your math problems solved is not the actual solution. Being a teacher and a mother, I would suggest you to learn the subject properly and do your homework by your own. You can ask your parents or teachers for help. Otherwise take help of a good tutoring site like SPAM or SPAM.