S Sarawr New member Joined Sep 6, 2009 Messages 1 Sep 6, 2009 #1 Hi, I'm having trouble with this question. Find the minimum for y y=(a+x)(b+x)\cx c,x,b,a>0 Can anyone help? Thanks.
Hi, I'm having trouble with this question. Find the minimum for y y=(a+x)(b+x)\cx c,x,b,a>0 Can anyone help? Thanks.
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,958 Sep 6, 2009 #2 Sarawr said: … y=(a+x)(b+x)\cx … Click to expand... Is what you typed supposed to be a rational function? y = [(x + a)(x + b)]/(cx) Does this exercise come from a calculus course? Are you trying to use the derivative? Why are you stuck? The more information that you provide to tutors, the better the responses that you will get back. Otherwise, we'll be playing a guessing game. Tell us what you already know about this exercise, and please check out the 'Read Before Posting' message.
Sarawr said: … y=(a+x)(b+x)\cx … Click to expand... Is what you typed supposed to be a rational function? y = [(x + a)(x + b)]/(cx) Does this exercise come from a calculus course? Are you trying to use the derivative? Why are you stuck? The more information that you provide to tutors, the better the responses that you will get back. Otherwise, we'll be playing a guessing game. Tell us what you already know about this exercise, and please check out the 'Read Before Posting' message.
D Denis Senior Member Joined Feb 17, 2004 Messages 1,700 Sep 6, 2009 #3 Sarawr said: Find the minimum for y y=(a+x)(b+x)\cx c,x,b,a>0 Click to expand... Hmmm....kinda silly....since c is in denominator, then minimum y = maximum c !
Sarawr said: Find the minimum for y y=(a+x)(b+x)\cx c,x,b,a>0 Click to expand... Hmmm....kinda silly....since c is in denominator, then minimum y = maximum c !
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,958 Sep 6, 2009 #4 With a, b, and c representing arbitrary and fixed positive Real constants, the Quadrant I minimum of the rational function y = (x + a)(x + b)/(cx) is: \(\displaystyle y \,=\, \frac{a}{c} \,+\, \frac{b}{c} \,+\, \frac{2ab}{c \; \sqrt{ab}}\) Unless I goofed.
With a, b, and c representing arbitrary and fixed positive Real constants, the Quadrant I minimum of the rational function y = (x + a)(x + b)/(cx) is: \(\displaystyle y \,=\, \frac{a}{c} \,+\, \frac{b}{c} \,+\, \frac{2ab}{c \; \sqrt{ab}}\) Unless I goofed.