Algebra Help: simplify {54 b^4 x^4 / 16 b x^2}^1/3

[Matholdie]

HELP!!!!!
Going back to school and I am struggling with my Algebra Class Can someone help? PLEASE!!!!!!!!!!

Simplify the expression:

Large Brackets {54b^4x^4/16bx^2}^1/3

Not understanding on how to do this.

THanks

 

[skeeter]

$\displaystyle [\frac {54b^4x^4}{16bx^2}]^{\frac{1}{3}}$

reduce the fraction inside the brackets first ...

$\displaystyle [\frac {27b^3x^2}{8}]^{\frac{1}{3}}$

raise every term to the 1/3 power ...

$\displaystyle \frac{27^{\frac{1}{3}}(b^3)^{\frac{1}{3}}(x^2)^{\frac{1}{3}}}{8^{\frac{1}{3}}}$

simplify ...

$\displaystyle \frac{3b \sqrt[3]{x^2}}{2}$

 

[Matholdie]

Algebra help

Skeeter,

When reducing the fraction how did you reduce the b^4 to a B^3?

I kept coming up with 3/2B 2/3x

 

[pka]

\(\displaystyle \L
\frac{{b^4 }}{b} = \frac{{b^4 }}{{b^1 }} = b^{4 - 1} = b^3\)

 

[Matholdie]

Algebra Help

Thanks PKA,