how do you do this? 1/(4x-4)-1/(2x^2-2)
S sarina00752 New member Joined Jun 5, 2010 Messages 1 Jun 5, 2010 #1 how do you do this? 1/(4x-4)-1/(2x^2-2)
W wjm11 Senior Member Joined Nov 13, 2004 Messages 1,417 Jun 5, 2010 #2 1/(4x-4)-1/(2x^2-2) Click to expand... I assume you want to simplify/create a single fraction. Always start by factoring in order to determine the lowest common denominator. 1/(4x-4) = 1/[4(x –1)] 1/(2x^2-2) = 1/[2(x – 1)] Notice that both denominators already have (x – 1) in them. Can you take it from here?
1/(4x-4)-1/(2x^2-2) Click to expand... I assume you want to simplify/create a single fraction. Always start by factoring in order to determine the lowest common denominator. 1/(4x-4) = 1/[4(x –1)] 1/(2x^2-2) = 1/[2(x – 1)] Notice that both denominators already have (x – 1) in them. Can you take it from here?
