It if awfully hard too read this. Here is my guess: \(\displaystyle \frac{(ab^2)(a^3b)}{a^2b^3}\) now apply the rules for exponents.Simplify the expressions. (a b2)(a3 b) / (a2 b3) I really don't get it , when we did it at school , please show me the method .
I have two comments.I often find that it can be very difficult to see small errors in problems when you don't understand how to solve them.
so just to clarify,
[MATH]\displaystyle \frac{(ab^2)(a^2b)}{a^2b^3}=\frac{(a^4b^3)}{a^2b^3}=\frac{(a^2)}{1}=a^2[/MATH]
This is pka's post with the error Jomo talked about corrected.
Yeah that is quite hilarious. I feel like the best part is that my post gives [MATH]a[/MATH] and not [MATH]a^2[/MATH]I'm guessing there is no way to edit the post and the mod even corrected pka's answer, so feel free to delete these posts when you find themI have two comments.
1) You did NOT start with the problem you initially posted.
2) Given what you started with you have an error.
Please try to fix your error and then do the original problem.
Now do one of the problems and show us your work.Yeah that is quite hilarious. I feel like the best part is that my post gives [MATH]a[/MATH] and not [MATH]a^2[/MATH]I'm guessing there is no way to edit the post and the mod even corrected pka's answer, so feel free to delete these posts when you find them
Jomo,Now do one of the problems and show us your work.
Nice to know that! I'll put you in for a holiday bonus this season.Jomo,
Please note that "hajfajv" is NOT the original poster of the problem (thread)!
No bonus-money needed. That will complicate my taxes.Nice to know that! I'll put you in for a holiday bonus this season.
No bonus-money needed. That will complicate my taxes.
Two tickets for getting out free from corner will do....