Algebra 2-Please Help!

[specialk835]

Please help!
Instructions. I need help to begin the problem because I don't know how to start.
6. Find the point-slope form of the equation of the line passing thorugh the points (6, -8) and (-2, -4).

7. Find an equation for the line: through (-6, -4) and vertical.

Thanks so much!

 

[Deleted member 4993]

Please help!
Instructions-
6. Find the point-slope form of the equation of the line passing thorugh the points (6, -8) and (-2, -4).

7. Find an equation for the line: through (-6, -4) and vertical.

Thanks so much!

Slope of a line passing through (x[sub:auc4yx4j]1[/sub:auc4yx4j],y[sub:auc4yx4j]1[/sub:auc4yx4j]) and (x[sub:auc4yx4j]2[/sub:auc4yx4j],y[sub:auc4yx4j]2[/sub:auc4yx4j]) is: m = (y[sub:auc4yx4j]2[/sub:auc4yx4j] - y[sub:auc4yx4j]1[/sub:auc4yx4j])/(x[sub:auc4yx4j]2[/sub:auc4yx4j] - x[sub:auc4yx4j]1[/sub:auc4yx4j])

Please show us your work, indicating exactly where you are stuck - so that we may know where to begin to help you.

 

[mmm4444bot]

Equations for vertical lines take the form: x = C, where C is the constant x-coordinate.

In other words, every point on a vertical line has the same x-coordinate.

Since they provided you with coordinates for a point on the line in exercise (7), you have the value of C.

(Note: There is no y variable in the equation of a vertical line.)