Algebra 2 help

brit500freestyle

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Feb 16, 2010
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I really need help with solving the following and showing all work.

1. 5x^3-2x^2+15x-6=0
2. x^2=6x+55
3. x^4-13x^2+36=0
4. 5x^3=-5000
 
brit500freestyle said:
I really need help with solving the following and showing all work.

1. 5x^3-2x^2+15x-6=0
2. x^2=6x+55
3. x^4-13x^2+36=0
4. 5x^3=-5000

Hi brit500freestyle,

Might help if you showed a little of what you can do here.

(1) Factor by grouping.

5x32x2+15x6=0\displaystyle 5x^3-2x^2+15x-6=0

x2(5x2)+3(5x2)=0\displaystyle x^2(5x-2)+3(5x-2)=0

Does that help? One real, two imaginary solutions.

(2) Set everything equal to zero.

x2=6x+55\displaystyle x^2=6x+55

x26x55=0\displaystyle x^2-6x-55=0

(x11)(x+5)=0\displaystyle (x-11)(x+5)=0

You should be okay from here...

(3) Just factor.

x413x2+36=0\displaystyle x^4-13x^2+36=0

(x24)(x29)=0\displaystyle (x^2-4)(x^2-9)=0

How's that for a start? Remember, there are 4 zeros here.

(4) 5x3=5000\displaystyle 5x^3=-5000

First, divide both sides by 5.

x3=1000\displaystyle x^3=-1000

Set everything equal to zero.

x3+1000=0\displaystyle x^3+1000=0

The left side is the sum of two cubes. There's a factoring pattern for that. You should know it. But here it is just for you:

a3+b3=(a+b)(a2ab+b2)\displaystyle a^3+b^3=(a+b)(a^2-ab+b^2)

Have fun finishing everything up. Ciao!
 
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