Alegbra 2 help

[xela24678]

Please help me with this problem:

(x^-3)(x^1/2)/(x^3/2)(x^-1)

this part^is on top of ^this part

thanks in advance

 

[Denis]

(x^-3)(x^1/2)/(x^3/2)(x^-1)

Rule: (x^a)(x^b) = x^(a+b)

So (x^-3)(x^1/2) = x^(-3 + 1/2) = x^(-5/2)

Is that enough?

 

[mmm4444bot]

What part do you need help with ? Have you learned this property ?

x^(-3) * x^(1/2)

x^(-3 + 1/2)

x^(-5/2)

When powers of the same base are multiplied together, we just add the exponents.

Now you do the same thing, in the denominator.

x^(3/2) * x^(-1)

After you simplify the line above, you have a new ratio. Finish, by using another property for a ratio of like powers.

When powers of the same base are in ratio, we subtract the bottom exponent from the top exponent, ike this:

x^(-5/2) over x^(1/2)

x^(- 5/2 - 1/2)

x^(-3)

Can you ask specific questions ?