Adding polynomials and simplifying

[Gr8fu13]

The instructions are to add (simpliy your answer) to:
(2v^4 - 2v^3 + 3v^2 + 11v - 8) + (v^5 + 7v^3 + 4v^2 - 3v + 5) + (- 5v^4 + v^2 - 5v - 7)

I tried to combine like terms:
v^5 + (2 + 1 - 5)v^4 + (- 2 + 7)v^3 + (3 + 4 + 1)v^2 + (11 - 3 - 5)v + (-8 + 5 - 7)

I came up with an answer of:
v^5 - 2v^4 + 5v^3 + 8v^2 + 3v - 10

Would this be correct? If not, can you pleas point out where I went wrong? Thanks!

 

[Deleted member 4993]

The instructions are to add (simpliy your answer) to:
(2v^4 - 2v^3 + 3v^2 + 11v - 8) + (v^5 + 7v^3 + 4v^2 - 3v + 5) + (- 5v^4 + v^2 - 5v - 7)

I tried to combine like terms:
v^5 + (2 + 1 - 5)v^4 + (- 2 + 7)v^3 + (3 + 4 + 1)v^2 + (11 - 3 - 5)v + (-8 + 5 - 7) ........Where did that come from?

I came up with an answer of:
v^5 - 2v^4 + 5v^3 + 8v^2 + 3v - 10

Would this be correct? If not, can you pleas point out where I went wrong? Thanks!

 

[Gr8fu13]

I substituted 1 for the V with no coefficient. That would be wrong?

 

[Gr8fu13]

Woops, I think I was using the V^5 in that one. I will just eliminate the 1?

 

[Gr8fu13]

So the answer would be:
v^5 - 3v^4 + 5v^3 + 8v^2 + 3v - 10

 

[mmm4444bot]

I substituted 1 for the V with no coefficient.

I think you misspoke; all powers of v have a coefficient.

Perhaps, you're trying to say that the polymomial

v^5 + 7v^3 + 4v^2 - 3v + 5

has no v^4 term. So you stuck one in.


That would be wrong?

Yes.

 

[mmm4444bot]

Whoops, I think I was using the V^5 in that one.

I'm not sure what you're trying to say here.


I will just eliminate the 1?

Yup.

2v^4 - 5v^4 = -3v^4

 

[mmm4444bot]

v^5 - 3v^4 + 5v^3 + 8v^2 + 3v - 10

I agree.

PS: The symbol V is not the same variable as the symbol v, so be careful with the shift key.