a ball is thrown straight up into the air from a point 64 feet above the ground with an intial speed of 48 feet/sec. what is the impact speed (in feet per second) when it strike the ground? [ignore air resistance, use g= 32 for the numerical value of the gravitational constant.]
basicly what i think i have to do
a(t) = -32
v(t) = -32t + 48
r(t) = -16t^2 + 48t + 64 or 64 = -16t^2 + 48t ??
from there to find impact speed i would have to find when the position is is 0. so i would factor -(16t^2 + 48t + 64) ?? then get ||V(t)|| ?
basicly what i think i have to do
a(t) = -32
v(t) = -32t + 48
r(t) = -16t^2 + 48t + 64 or 64 = -16t^2 + 48t ??
from there to find impact speed i would have to find when the position is is 0. so i would factor -(16t^2 + 48t + 64) ?? then get ||V(t)|| ?
