sofidoremi
New member
- Joined
- Dec 9, 2009
- Messages
- 1
How do you solve |2x+6|=8? Today our teacher gave us some notes about case 1 and case 2 to solve this but I don't understand how he did the question. This is an example:
Case 1: |2x+6|=8
x<(-3)
-(2x+6)=8
x=(-7)
so where why is x<-3? where did the -3 come from?
case 2:
x is less than or equal to -3
2x+6=8
x=1
x=-7, 1
I don't understand how this is done or why you do what you do for this. Can you please explain and walk me through the steps so I can understand it?
Thanks!
Case 1: |2x+6|=8
x<(-3)
-(2x+6)=8
x=(-7)
so where why is x<-3? where did the -3 come from?
case 2:
x is less than or equal to -3
2x+6=8
x=1
x=-7, 1
I don't understand how this is done or why you do what you do for this. Can you please explain and walk me through the steps so I can understand it?
Thanks!