Why do you think that is wrong?View attachment 34355i have found the minimum of this function is (0,0) and max is (1,1) but i feel like I am doing something wrong![]()
the boundaries would be (0,0),(1,0),(1,1) and if plugged in (0,0) gives lowest value and (1,1) gives highestWhy do you think that is wrong?
Please share your work!
i found that the critical point would be (-1,2) but it is outside the boundaries so it can not be used also i found that the boundary would be those 3 points (0,0) (1,0) and (1,1)Two questions.
Is the boundary of the domain defined by three points or by some number of curves?
Does the function have one or more local extrema at any point inside the boundaries?
so what would the correct answer for min and max be ?The boundary of the domain is not defined by three points. It is defined by three curves, namely
y = 0,
x = 1, and
y = x^2.
Graph the domain and you will see why. So, you must test all points on the boundary. Then you can be confident of your answer.
In any case, what are the minimum and maximum values in that domain?
[math] z = x^2 + xy + y, \text { where } 0 \le x \le 1, \ 0 \le y \le x^2.\\ \therefore \ 0 \le x \le 1, \text { and } y = 0 \implies \min(z) = \text {WHAT, and } \max(z) = \text { WHAT?}\\ x = 0 , \text { and } y \le x^2 = 0 \implies \min(z) = \text {WHAT, and } \max(z) = \text {WHAT?}\\ 0 \le x \le 1 \text { and } 0 \le y \le x^2 \implies \min(z) = \text {WHAT, and } \max(z) = \text {WHAT?} [/math]so what would the correct answer for min and max be ?
Here is how I would do this problem. Luckily this method will work with this f(x,y).View attachment 34355i have found the minimum of this function is (0,0) and max is (1,1) but i feel like I am doing something wrong![]()