About this grafh

DanieldeLucena

New member
Joined
Jul 29, 2010
Messages
39
I want to know what's the function of this grafh below
[attachment=1:2011yflp]1.JPG[/attachment:2011yflp]
It's almost like this
[attachment=0:2011yflp]2.JPG[/attachment:2011yflp]
 
The graphic is almost illegible; your axis and values are clear, but I can only see shades of gray behind that.

How does the graphic differ from the absolute-value quadratic you've shown?

Thank you! :wink:
 
Re:

stapel said:
How does the graphic differ from the absolute-value quadratic you've shown?

Here is the difference:

For \(\displaystyle \ x < -3 \ \ and \ for \ \ x >3, \\) the sections of the graph of the quadratic point down,
as opposed to the one in blue, where they both point up for these intervals.
 
lookagain said:
stapel said:
How does the graphic differ from the absolute-value quadratic you've shown?

Here is the difference:

For \(\displaystyle \ x < -3 \ \ and \ for \ \ x >3, \\) the sections of the graph of the quadratic point down,
as opposed to the one in blue, where they both point up for these intervals.

Yes, you're right. Is this I want to know, how to get this in only one function.
 
DanieldeLucena said:
lookagain said:
Here is the difference:
For \(\displaystyle \ x < -3 \ \ and \ for \ \ x >3, \\) the sections of the graph of the quadratic point down,
as opposed to the one in blue, where they both point up for these intervals.

Yes, you're right. Is this I want to know, how to get this in only one function.

DanieldeLucena,

it *already* is one function. For instance, it meets the vertical line test. Even if it were
described by a piece-wise function, that would be one function. So, what you must be
meaning is the expression on the right side of the equation (y = expression in x) is not a
piece-wise function, but instead is a closed form of a one-line expression involving only
the x variable. This would presumably be an expression with at least one absolute value sign
as part of it.
 
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