spacewater
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How come \(\displaystyle y = x^{2/3}\) and \(\displaystyle y = cube\sqrt {x^2}\) show different result on graphing utility?
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a quick question regarding graphing calculator
- Thread starter spacewater
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D
Deleted member 4993
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do you mean :
spacewater said:How come \(\displaystyle y = x^{2/3}\) and \(\displaystyle y = \sqrt[3] {x^2}\) show different result on graphing utility?
spacewater
Junior Member
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- Jul 10, 2009
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Subhotosh Khan said:do you mean :
spacewater said:How come \(\displaystyle y = x^{2/3}\) and \(\displaystyle y = \sqrt[3] {x^2}\) show different result on graphing utility?
\(\displaystyle y = x^{2/3}\) = \(\displaystyle y = \sqrt[3] {x^2}\)
how come the graphic utility shows 2 different answer?
D
Deleted member 4993
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spacewater said:Subhotosh Khan said:do you mean :
spacewater said:How come \(\displaystyle y = x^{2/3}\) and \(\displaystyle y = \sqrt[3] {x^2}\) show different result on graphing utility?
\(\displaystyle y = x^{2/3}\) = \(\displaystyle y = \sqrt[3] {x^2}\)
how come the graphic utility shows 2 different answer?
What are the two different answers - what were the 'x's?
fasteddie65
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- Nov 1, 2008
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It depends on which calculator you are using.
On my TI-84, both graphs are the same, but on the TI-83 the graph of y = x^(2/3) is not the same as y = (cube root x)^2. I think it is because it will only graph x^(2/3) for non-negative values of x, because it uses logarithms to compute the values. As you probably know, logarithms of negative numbers are "undefined."
On my TI-84, both graphs are the same, but on the TI-83 the graph of y = x^(2/3) is not the same as y = (cube root x)^2. I think it is because it will only graph x^(2/3) for non-negative values of x, because it uses logarithms to compute the values. As you probably know, logarithms of negative numbers are "undefined."