A question regarding Rationalization

H

haro

New member
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Feb 5, 2009
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Hi everyone, nice to meet you all. I am new here, so this is my first post...a question haha.

Well, trying to solve a problem, I got stuck in the process. The truth is that I am not sure if the answer I obtained is the final answer, or it can be further simplified.
Here is the problem.

I hope you understand, since I can not use any equation editor in here, I am posting the URL of a image containing the exercise.

http://img144.imageshack.us/my.php?image=ex1lu0.jpg


I thank your help in advance.

Haro
 
Hello, this is Haro again.

I forgot to post an explanation of what I did.

Well, I basically rationalized the denominator twice. First, I rationalized the term under 3, and after that I eliminate the main square root. After that, I rationalized the denominator again by multiplying it by its conjugate.

I am not completely sure if that's the most suitable method.

Please refer to my first post. There you will find the URL of the image of my exercise.

Thanks once again.
 
haro said:
Well, trying to solve a problem, I got stuck in the process. The truth is that I am not sure if the answer I obtained is the final answer, or it can be further simplified.
Here is the problem.
since I can not use any equation editor in here,
Click to expand...
\(\displaystyle \frac{3}{{\sqrt {3 - \sqrt 3 } }} = \frac{{3\sqrt {3 - \sqrt 3 } }}{{3 - \sqrt 3 }} = \frac{{\left( {\sqrt {3 - \sqrt 3 } } \right)\left( {3 + \sqrt 3 } \right)}}{2}\)

since I can not use any equation editor in here
See above.
Oh yes you can! You just must learn LaTeX.
 
Well, thanks Pka.

However, I don't know how you move from step 2 to step 3. If you don't mind, can you show me how you got that answer?

best,

Haro
 
\(\displaystyle \frac{{3\sqrt {3 - \sqrt 3 } }}{{\left( {3 - \sqrt 3 } \right)}}\frac{{\left( {3 + \sqrt 3 } \right)}}{{\left( {3 + \sqrt 3 } \right)}} = \frac{{3\left( {\sqrt {3 - \sqrt 3 } } \right)\left( {3 + \sqrt 3 }\right)}}{6} = \frac{{\left( {\sqrt {3 - \sqrt 3 } } \right)\left( {3 + \sqrt 3 } \right)}}{2}\)
 
Ok thanks pka,

In fact, you answer is very similar to the one I got to begin with. So, i can infer that the method I used is correct.

Haro
 
Ok thanks pka,

In fact, you answer is very similar to the one I got to begin with. So, i can infer that the method I used is correct.

Ps. If someone else has another way to do this exercise, I will appreciate if you show me how.

Best regards,


Haro
 
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