A Question about Number Systems

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Thunderstorm

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Nov 5, 2016
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Hi,I've got 8 questions and Im from different country,ill try to translate them so forgive me if they are misunderstood.Can you help me? Thank you so much?

Question 1:

a,b,c are each different numbers,What is the littlest value that 2a+3b-c can get? The answer is - 7 but i can't find the steps.:confused:
 
Err... sorry, but I think some crucial information got lost in the translation. The problem states that \(\displaystyle a \ne b \ne c\) and then asks you minimize (i.e. find the smallest possible value of) \(\displaystyle 2a+3b-c\). You say the given answer is -7, but for that to be true, there must be additional constraints on the variables a, b, and c. For instance, if \(\displaystyle a=-57\), \(\displaystyle b=2\), and \(\displaystyle c=8\), then:

\(\displaystyle 2a+3b-c=2(-57)+3(2)-8=-114+6-8=-116\)

So, clearly, something more is going on here.
 
Thunderstorm said:
Hi,I've got 8 questions and Im from different country,ill try to translate them so forgive me if they are misunderstood.Can you help me? Thank you so much?

Question 1: a,b,c are each different numbers,What is the littlest value that 2a+3b-c can get? The answer is - 7 but i can't find the steps.
Click to expand...

You need a better translator.
 
How does that solve it? The problem, as stated, as to show that -7 was the smallest possible value of 2a+ 3b- c. Showing that there exist values of a, b, and c that make the value -7 does not show that -7 is the smallest possible value! As pka showed before, there are other values of a, b, and c that make this much smaller than -7. Again, please post the complete statement of the problem.
 
HallsofIvy said:
How does that solve it? The problem, as stated, as to show that -7 was the smallest possible value of 2a+ 3b- c. Showing that there exist values of a, b, and c that make the value -7 does not show that -7 is the smallest possible value! As pka showed before, there are other values of a, b, and c that make this much smaller than -7. Again, please post the complete statement of the problem.
Click to expand...

There aren't other values they can be because it says numbers (how you call it ? numerals? i mean one-digit numbers so we need to gave the highest value(9) to the negative one which is c and the littlest value to the b and again little value for a.Using the word "numbers" instead of "one-digit number" caused misunderstanding but I already wrote the whole question and the answer is-7 as i said.Ps.I dont use a translator its just my english,wrong word choices and lack of technical terms and Im new at math,but it doesnt stop me getting help and studying math,does it? :oops:
 
So a, b, and c must be integers between 0 and 9? Since you Engish is far better than my (put language of choice here) I wont complain about that.
 
Thunderstorm said:
Okay, i thought them as c=-9 b=0 and a=1, 2.1+3.0-9= -7 its solved,Thank you so much for your help it gave me the idea to solve it!
Click to expand...

Yeah you are correct. According to the logic that should be the answer

c>a>b

c = 9
b = 0
a = 1
 
Denis said:
If you knew that we're dealing with 0 to 9,
and that a<>b, then why did you post the problem?
Click to expand...

I knew that but I didnt know which one I should give the highest value i thought about giving (-9) to the b to make result highest (or the littlest as we say) though it didnt mention they are integers @HallsofIvy (Thank you! but the problem doesnt include the information that they are integers! it says just numerals which are "0,1,3,...") ,also I didnt think about giving "0" value to a number either.I thought,9,1 and 2 as values which led to more confusion.I have got other problems just like that and there are small tricks I need to realize but its Math ,when you cant realize,you cant solve it thats why i need anothers opinions and someone making me realize the things i didnt see at first point.
 
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