A permutation problem based on code word

sanjeev

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A Code Word is to consist of two distinct English alphabets followed by 2 distinct numbers between 1 and 9.How many such codes are possible.



THE ANSWER GIVEN IS 27300 BUT I DON'T KNOW HOW TO DO IT...........................
 
A Code Word is to consist of two distinct English alphabets followed by 2 distinct numbers between 1 and 9.How many such codes are possible.
What do you mean by "two distinct English alphabets"? Do you perhaps mean "alphabetic characters", so you're needing two different letters?

THE ANSWER GIVEN IS 27300 BUT I DON'T KNOW HOW TO DO IT.
Okay, okay; there's no need to SHOUT. :-(

Have you done any exercises of this sort before, or are you needing lesson instruction first? Thank you! ;)
 
The first can be any letter. How many choices are there? The second can be any letter except whatever you used for the first. How many choices are there? The third can be any digit from 1 to 9. How many choices are there? The fourth can be any digit except whatever you used for the third. How many choices are there?

"Fundamental law of counting"- if you can do one thing in m different ways and a second in n different ways, you can do both of them in mn different ways.
 
The third [digit] can be any digit from 1 to 9.

If the book's answer for the number of permutations is correct, then I think we need to interpret the word "between" literally -- that is, the digits in-between 1 and 9.

In this case, the given phrase "2 distinct numbers between 1 and 9" would be better phrased as "two distinct digits from 2 through 8".

Cheers :)
 
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