A nonzero value for c such that f(c)=c

hcinic

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Pls help! A nonzero value for c such that f(c)=c

Hi! I'm new here and am struggling with a HW problem in my Precalculus class.
The problem states to find a value for 'c' such that f(c)=c

the equation is: x^2 - 4x - c

I know the answer is c=6, but do not know how to get here algebraically. Any help would be greatly appreciated!
 
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Hi! I'm new here and am struggling with a HW problem in my Precalculus class.
The problem states to find a value for 'c' such that f(c)=c

the equation is: x^2 - 4x - c

I know the answer is c=6, but do not know how to get here algebraically. Any help would be greatly appreciated!

\(\displaystyle f(c) = c^2-4c-c = c^2-5c\)

Set this equal to \(\displaystyle c\) and use your knowledge of solving quadratic equations to solve for the value(s) of \(\displaystyle c\).
 
Do you understand function notation?

The given function is f(x) = x^2 - 4x - c

They ask you to find a value for c that equals the number f(c).

The symbol f(c) is function notation for the expression c^2 - 4c - c.

In other words, f(c) is a symbol that represents x^2 - 4x - c only after we substitute x = c.

So, set the expression for f(c) equal to c, and solve that equation.
:cool:

PS: In future posts, please mention what you've thought about or tried thus far. Cheers.
 
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\(\displaystyle f(c) = c^2-4c-c = c^2-5c\)

Set this equal to \(\displaystyle c\) and use your knowledge of solving quadratic equations to solve for the value(s) of \(\displaystyle c\).

correct me if i'm wrong but

c^2 - 5c = 0 gives me c = 0 and 5

but this can't be right
 
\(\displaystyle f(c) = c^2-4c-c = c^2-5c\)

Set this equal to \(\displaystyle c\) and use your knowledge of solving quadratic equations to solve for the value(s) of \(\displaystyle c\).



(OP, I took credit for this post as the author abdicated it.)
 
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