a matrix problem. Possibly very simple. I dont understand matrix at all.
- Thread starter ncc1701d
- Start date
Well, as you can probably see, the forum does not preserve white-space based formatting, so your message got a bit jumbled in transmission. I think the following is what you meant. Please reply with any necessary corrections:
\(\displaystyle \begin{pmatrix}0.0245658\\ 0.0209381\\ 0.9994789\end{pmatrix}\times \begin{pmatrix}-0.0864092\\ -0.9960834\\ -0.0187432\end{pmatrix}=\begin{pmatrix}0.9959568\\ -0.0859037\\ -0.0262788\end{pmatrix}\)
Assuming the above is correct, the "x" symbol indicates that you're meant to take the cross product of the two vectors, and it will equal the given result. My only caution is that the cross product of the two given vectors is not exactly equal to the given result, but it's off by a little bit due to rounding errors. These values you wrote seem to be decimal approximations of some values, and my bet is if you instead use the actual exact values (in fraction form), and then perform the cross product, you'll get the real answer. If you need a refresher on how the cross product of two 3-dimensional vectors work, try this website.
\(\displaystyle \begin{pmatrix}0.0245658\\ 0.0209381\\ 0.9994789\end{pmatrix}\times \begin{pmatrix}-0.0864092\\ -0.9960834\\ -0.0187432\end{pmatrix}=\begin{pmatrix}0.9959568\\ -0.0859037\\ -0.0262788\end{pmatrix}\)
Assuming the above is correct, the "x" symbol indicates that you're meant to take the cross product of the two vectors, and it will equal the given result. My only caution is that the cross product of the two given vectors is not exactly equal to the given result, but it's off by a little bit due to rounding errors. These values you wrote seem to be decimal approximations of some values, and my bet is if you instead use the actual exact values (in fraction form), and then perform the cross product, you'll get the real answer. If you need a refresher on how the cross product of two 3-dimensional vectors work, try this website.
pka
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